2. In a calorimeter, 40.0g water at room temperature (20.4 C) was mixed with 60.0 g of water that was

Question

initially 48.9 C. The resulting mixture reached a maximum temperature of 37.3 C. Calculate each of the
following.
a) The heat released by the hot water.
b) The heat absorbed by the room temperature water.
c) The calorimeter constant.

Answer 1

It doesn't help to post essentially the same question under another screen name.

Answer 2

For part A) I know it goes something like this. 40.0g(4.184)(48.9-37.3). But it asks for heat released by hot water i'm not exactly sure what to do.

I know c is A)-B)

Answer 3

See if you can do the others with the help of the previous problem.

Answer 4

A)60.0g(4.814)(48.9-37.3)=3350.544
B)40.0(4.814)(20.4-37.3)=3254.264
C)A-B= 96.28