ΔE = q - w
ΔE is the change in internal energy of a system
q is the heat flowing into the system
w is the work being done by the system
The 2424 J is released to the surroundings. It should be assigned a negative sign. The 6 KJ is work done against the surroundings. That is energy released, too. Assign algebraic signs carefully and see what value for delta E you get.
When 1 mol of a gas burns at constant pressure, it produces 2424 J of heat and does 6 kJ of work.
How do i calculate delta E for this problem? I tried q+w but that didn't work for me. I got the answer wrong.
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