What would be the pH of .002 moles of HNO3 dissolved in 2 L of water?

Answer 1

To find the pH of the solution, we need to calculate the concentration of H+ ions in the solution first.

Given:
- Moles of HNO3 = 0.002 moles
- Volume of water = 2 L

Molarity of the solution:
M = moles of solute/volume of solution in liters
M = 0.002 moles / 2 L
M = 0.001 M

Since HNO3 dissociates completely in water, the concentration of H+ ions in the solution will be equal to the molarity of the HNO3.

[H+] = 0.001 M

Now, we can calculate the pH of the solution using the formula:
pH = -log[H+]
pH = -log(0.001)
pH = -(-3)
pH = 3

Therefore, the pH of 0.002 moles of HNO3 dissolved in 2 L of water would be 3.