Determine the pH of the following solutions.

1) 0.600 M HCl
2) 0.052 moles of H2SO4 dissolved in 4.2 L of water.
3)5.6 grams HNO3 dissolved in 450 ml of water.
4) 2.5 grams of NaOH dissolved in 500 mL of water.
5) adding 2 grams NaH dissolved in 0.56 L of water.
6) 20 mL of 0.27 M HNO3 is diluted to 500 mL.

2 answers

Tyra, you really need to help by answering the questions we ask. I need to know WHAT you don't understand about a problem.

1. For strong acids like HCl which ionize 100%, then pH = -log HCl)

3. Convert 5.6 g to mols. mols = grams/molar mass. Then the definition of molarity is M = mols/L. You know mols from the conversion you made from 5.6 grams and you know it is in 0.450 L.
4. is the same procedure as 3.

6. For dilutions use the dilution formula of
mL1 x M1 = mL2 x M2
20 x 0.27 = 500 x ?
Solve for ?
0.0108