1-digit numbers: 9
2-digits: 90, so total digits used = 2*90+9 = 189
3-digits: 900, so total digits = 3*900+189 = 2889
4-digits: 9000, so total digits - 4*9000+2889 = 38,889
38889-23478 = 15411 = 3852*4 + 3
So, it will be the 3rd digit of the 3853rd 4-digit number.
999+38583 = 39582
Hmmm. I get 5, not 6.
Better check my logic and math.
What will be the 23,478th digit of the number 1234567891011121314......?
answer is 6. explain in easy way.
4 answers
1-digit numbers: 9
2-digits: 90, so total digits used = 2*90+9 = 189
3-digits: 900, so total digits = 3*900+189 = 2889
4-digits: 9000, so total digits - 4*9000+2889 = 38,889
38889-23478 = 15411 = 3852*4 + 3
So, it will be the 3rd digit of the 3853rd 4-digit number.
999+38583 = 39582
Hmmm. I get 5, not 6.
Better check my logic and math.
0 0
2-digits: 90, so total digits used = 2*90+9 = 189
3-digits: 900, so total digits = 3*900+189 = 2889
4-digits: 9000, so total digits - 4*9000+2889 = 38,889
38889-23478 = 15411 = 3852*4 + 3
So, it will be the 3rd digit of the 3853rd 4-digit number.
999+38583 = 39582
Hmmm. I get 5, not 6.
Better check my logic and math.
0 0
Nice repost.
Too bad you didn't have anything to add ...
Too bad you didn't have anything to add ...
The south shall rise again