Asked by Anonymous

1234567891011121314..........
What is the 2020th digit in the above sequence

5 years ago

Answered by Anonymous

Please answer my question

5 years ago

Answered by oobleck

impatient much?
1-digit numbers: 9
2-digit numbers: 90
so starting at 100, that has used up 9+2*90 = 189 digits
2020-189 = 1831
That's 610 3-digit numbers, plus 1 digit.
so, what is the 611th 3-digit number?

5 years ago

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