What volumes of 0.00250M salicylic acid solution and 0.1M ferric chloride solution would you need to make 50mL of a 0.00350M solution?
4 answers
0.00350 M solution in what? salicylic acid? ferric chloride? the product? If the product, what product?
I'm sorry, of the product: Iron-salicylate complex.
I assume the equation is
Fe^3+ + SYL ==> Fe(SYL)^3+
You want 50.00 mL x 0.00350M = 0.175 millimols of the complex.
So you will need 3x that of SYL and 1x that for Fe^3+.
So mL x M = millimols.
For Fe you need mL x 0.1M = 0.175 mmol.
For SYL you need mL x 0.00250 = 3*0.175 mmol.
Solve for mL in each case.
Fe^3+ + SYL ==> Fe(SYL)^3+
You want 50.00 mL x 0.00350M = 0.175 millimols of the complex.
So you will need 3x that of SYL and 1x that for Fe^3+.
So mL x M = millimols.
For Fe you need mL x 0.1M = 0.175 mmol.
For SYL you need mL x 0.00250 = 3*0.175 mmol.
Solve for mL in each case.
When I solve for Fe I get 1.75mL and for SYL I get 210mL. That can't be correct if we are trying to make 50mL.
The equation is:
Salicylic Acid + [Fe(H2o)6]^+3 ---> Iron-salicylate complex
The equation is:
Salicylic Acid + [Fe(H2o)6]^+3 ---> Iron-salicylate complex