CH4 + 2O2 ==> CO2 + 2H2O
You may use a shortcut when dealing with gases and use volume as if they were mols directly. Therefore, we will use 2.65 L CH4. Convert to L O2.
2.65 L CH4 x (2 mols O2/1 mols CH4) = 2.65 x 2/1 = ? L O2.
Then convert ?L O2 at STP to L O2 at the conditions of the problem.
What volume of oxygen(in Liters) at 25 degrees C and 1.05 atm is needed to completely combust 2.65L of methane, measured at STP
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