If a tank contains 55.2 g of butane, what volume, in liters, of oxygen is needed to burn all the butane at 0.850 atm and 25 degrees Celsius? Need to show work too.

Answer 1

2C4H10 + 13O2 ==> 8CO2 + 10H2O

mols butane = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols butane to mols O2.
Use PV = nRT and solve for V O2 at the conditions listed.