per the reaction equation ... each mole of KClO3 produces 1.5 moles of O2
13.5 g / (molar mass KClO3) = moles KClO3
... multiply by 1.5 to find moles of O2
each mole of O2 has a volume of 22.4 L
What volume of oxygen gas will be produced when 13.5 g of potassium chlorate is decomposed at STP?
2KClO3(s) → 2KCl(s) + 3 O2(g)
2 answers
when 25 g of potassium chordate decomposes 15 g of paoassium chloride is produced. how many miles of oxygen has are produced