What volume of glycerine C3H8o3. Density 1.26g/ml, should be taken to obtain 2.50mol of glycerine

Answer 1

Assuming glycerol is 100%, then
mass of 1 L = 1.26 g/mL x 1000 mL = 1260 grams in a liter.
molar mass glycerin = 92
1260/92 = 13.7 mols/L
13.7 mols/L x #L = 2.50 mols.
Solve for #L.