what volume of glycerine C3H8O3, with a density of 1.26 g/mL should be taken to obtain 2.50 ml of glycerine?
3 answers
what volume of glycerine CHO with 1.26 must be taken to obtain 2.50 mole of glycerine
Answer to this question
Given number of moles to be 2.5mol, we can use it and the molar mass of glycerine which is 92.11g/mol to determine it's mass. That is,
m=nMr
m=2.50mol*92.11g/mol
m=230g
Density is s ratio of the mass and the volume, so we use this relationship to find the volume to obtain 2.5mol,C3H8O3
V=m/D
V=230g/1.26g/ml
V=183ml
m=nMr
m=2.50mol*92.11g/mol
m=230g
Density is s ratio of the mass and the volume, so we use this relationship to find the volume to obtain 2.5mol,C3H8O3
V=m/D
V=230g/1.26g/ml
V=183ml