snow, Taylor, Shania
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What volume of distilled water should be added to 500ml of a solution of sulphuric acid to 90% by weight, density 1.81 g.mL-1, to obtain a 10 Molar solution?
2 answers
First determine the M of the initial H2SO4. That's
1.81 g/mL x 1000 mL x 0.90 x 1/98 = ?M which I will call y.
Then mL1 x M1 = mL2 x M2
500 mL x yM = mL2 x 10
Solve for mL2 which is approx 850. Subtract 500 from that to see what volume should be added. The answer is approx 350.
1.81 g/mL x 1000 mL x 0.90 x 1/98 = ?M which I will call y.
Then mL1 x M1 = mL2 x M2
500 mL x yM = mL2 x 10
Solve for mL2 which is approx 850. Subtract 500 from that to see what volume should be added. The answer is approx 350.
1 answer