C1V1=C2V2
(a)
1.0 mol/L * 0.2L = C2 * 1.0 L
Solve for C2
(b)
C2 (from a) * 25 cm³ = (1.6 mol/L)*V2
Solve for V2.
200cm^3 of 1.0 mol dm^-3 sulphuric acid,H2SO4 is poured into a 250 cm^3 volumetric flask.Distilled water is then added to make 250 cm^3 of solution.
(a)What is the molarity of the diluted acid solution?
(b)What is the volume of 1.6 mol dm^-3 sodium hydroxide,NaOH solution needed to neutralise 25 cm^3 of the diluted acid?
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