A "Bayer brand of aspirin was dissolved in some sodium hydroxide and transferred to a 100.0 ml volumetric flask and diluted to the mark with distilled water. A 3.1ml aliquot of this solution was transferred to a second 100.0 ml volumetric flask and diluted to the mark with iron (Il) chloride solution. The concentration of the iron (II) salicylate complex was found to be 0.046mM. What was the original concentration of A.S.A (aspirin) in the original solution, in mM?

2 answers

I wonder if you made a typo. According to the information I have it is FeCl3 (not FeCl2) that forms a complex with ASA which is [Fe(C6H4OCOO)]+.. In any event; however, whether FeCl2 or FeCl3 the complex is a 1:1 ratio of Fe to ASA.
0.046 mM in the final 100 mL. So the first 100 mL volumetric flask has 0.046 mM x (100 mL/3.1 mL) = ? mM in the first flask (original solution of ASA). Since the ratio is 1 mol Fe to 1 mol ASA. that is the concn of ASA.
@DrBob222 You're right. My apologies. A "Bayer brand of aspirin was dissolved in some sodium hydroxide and transferred to a 100.0 ml volumetric flask and diluted to the mark with distilled water. A 2.2 ml aliquot of this solution was transferred to a second 100.0 ml volumetric flask and diluted to the mark with iron (IlI) chloride solution. The concentration of the iron (III) salicylate complex was found to be 0.048mM. What was the original concentration of A.S.A (aspirin) in the original solution, in mM?