What volume of 0.900 M HCl is required to complete neutralize 50.0 ml of a 0.500 M Ba(OH)2 solution?

Answer 1

balance the equation. You will see that it takes two moles of HCl for each mole of Ba(OH)2

2molesHCl=1moleBa(OH)2
2*.9*Va=1*.5*50ml
solve for volume of acid, Va