what volume of 0.4 M HCl is required to neutralize 100.0 mL of 0.3 M LiOH?

Answer 1

For a 1:1 ratio of acid to base, which you have, mL x M = mL x M.
mL(HCl) x 0.4 M = mL(LiOH) x 0.3 M
Solve for mL(HCl).

Answer 2

(ii) If 22.0 mL of 2.5 M HCl was used to neutralize 50.0 mL of a Ba(OH)2 solution, what was the concentration of the base?

Answer 3

75 ml of hcl

Answer 4

0.6