The sulfuric acid is .4N .
.4N(volume)=.178N*50ml
solve for volume
What volume of 0.200 M H2SO4 will be needed to neutralize 50mL of 0.178 N NaOH?
i don't even know how to start
4 answers
3.56mL?
No, not even close.
You want (50*0.178)/0.4 = ??
You want (50*0.178)/0.4 = ??
22.25 ml?
2 answers