H2SO4 + 2NaOH ==> Na2SO4 + 2H2O
mols NaOH = M x L = ?
mols H2SO4 = 2x mols NaOH (look at the coefficients n the balanced equation.)_
M H2SO4 = mols H2SO4/L H2SO4
A 25.0-mL sample of H2SO4 is neutralized with NaOH. What is the concentration of the H2SO4
if 35.0 mL of 0.150 M NaOH are required to
completely neutralize the acid?
4 answers
.105 M
0.180M
There seems to be a mistake in the given information. We can calculate the concentration of H2SO4 using the given information as follows:
NaOH and H2SO4 react in a 1:2 molar ratio. Therefore, the number of moles of H2SO4 in the given sample can be calculated as:
moles H2SO4 = 2 × moles NaOH
moles NaOH = concentration of NaOH × volume of NaOH used = 0.150 M × 35.0 mL = 0.00525 moles
moles H2SO4 = 2 × 0.00525 = 0.0105 moles
The volume of H2SO4 used is 25.0 mL = 0.0250 L
Therefore, the concentration of H2SO4 is:
concentration of H2SO4 = moles H2SO4 / volume of H2SO4 used = 0.0105 moles / 0.0250 L = 0.420 M
So, the concentration of H2SO4 is 0.420 M.
NaOH and H2SO4 react in a 1:2 molar ratio. Therefore, the number of moles of H2SO4 in the given sample can be calculated as:
moles H2SO4 = 2 × moles NaOH
moles NaOH = concentration of NaOH × volume of NaOH used = 0.150 M × 35.0 mL = 0.00525 moles
moles H2SO4 = 2 × 0.00525 = 0.0105 moles
The volume of H2SO4 used is 25.0 mL = 0.0250 L
Therefore, the concentration of H2SO4 is:
concentration of H2SO4 = moles H2SO4 / volume of H2SO4 used = 0.0105 moles / 0.0250 L = 0.420 M
So, the concentration of H2SO4 is 0.420 M.
1 answer