What value of y would make the expression yb−6+7+2b−3b+1 equivalent to 5b+2?(1 point

Answer 1

To make the two expressions equivalent, we need to find the value of y that will make the left side equal to the right side.

First, we need to simplify the left side of the equation:

yb – 6 + 7 + 2b – 3b + 1 = 5b + 2

Combine like terms:

yb + 2b – 3b – 6 + 7 + 1 = 5b + 2

yb – 1 = 5b + 2

Next, let's isolate the variable y by moving all terms involving y to one side of the equation:

yb – 1 = 5b + 2

Subtract 5b from both sides:

yb - 5b - 1 = 2

Now we have:

-4b = 3

Divide both sides by -4 to solve for b:

b = -3/4

Therefore, the value of y that would make the expression yb−6+7+2b−3b+1 equivalent to 5b+2 is -3/4.