C6H5NH2 HOH ==> C6H4NH3^+ + OH^-
Set up an ICE chart, substitute into Kb for aniline of
Kb = (C6H5NH2^+)(OH^-)/(C6H5NH2)
Convert pH to pOH, then to (OH^-) which equals (C6H5NH3^+) and solve for (C6H5NH2).
Post your work if you gets stuck.
What stoichiometric concentration of the indicated substance is required to obtain an aqueous solution with the pH} value shown below?
aniline (C6H5NH2) for PH of 8.90
2 answers
0.147