What pressure is required to reduce 34 mL of a gas at standard conditions to 16 mL at a temperature of 20◦C

Answer 1

P1V1=nRT1
P2V2=nRT2

P2=P1*V1/V2*T2/t1

P2=1atm*34/16*293/273

Answer 2

What pressure is required to reduce 34 mL of
a gas at standard conditions to 16 mL at a
temperature of 20◦C?

Answer 3

0.000026566