What minimum frequency of light is required to ionize potassium?The energy required to ionize potassium is 419kJ/mol?

Answer 1

E = h*frequency

I would convert 419 kJ/mol to J, then divide by 6.022 x 10^23 to convert to J/atom, substitute into the equation and solve for frequency.

Answer 2

I got 4.6102*10^-6 and it is wrong...Can you step me through the problem?

Answer 3

419 kj into jules =
419000

Divide by avogadro's number

419000/6.022e23

Divide that by Planck's Constant for the answer.

Answer 4

V=E/h so (149000/(6.026x10^-34)(6.022x10^23) =1.05x10^15. s^-1