What might be the mass of a positive ion that is moving 1x10^7m/s and is bent into a circular path of radius 1.55m by a magnetic field of 0.134T?

Answer 1

m v^2/R = F = Q v B
so
m = Q v B R / v^2 = Q B R / v
where Q = electron charge = 1.6*10^-19

Answer 2

SO THE DERIVE FORMULA IS m= QBR / v ?