What method is used to prepare lead iodide which is an insoluble salt
2 answers
Write an ionic equation for the reaction in the preparation of lead (2)iodide salt,including state symbols
The equation for the preparation of lead (2) iodide salt is:
Pb(NO3)2 (aq) + 2KI (aq) → PbI2 (s) + 2KNO3 (aq)
Where:
Pb(NO3)2 (aq) is lead (2) nitrate in aqueous solution
2KI (aq) is potassium iodide in aqueous solution
PbI2 (s) is lead (2) iodide, the insoluble salt
2KNO3 (aq) is potassium nitrate in aqueous solution
The ionic equation for this reaction is:
Pb2+ (aq) + 2NO3- (aq) + 2K+ (aq) + 2I- (aq) → PbI2 (s) + 2K+ (aq) + 2NO3- (aq)
Where:
Pb2+ is lead (2) ion, which is the cation in lead (2) nitrate
NO3- is nitrate ion, which is the anion in lead (2) nitrate and potassium nitrate
K+ is potassium ion, which is the cation in potassium iodide and potassium nitrate
I- is iodide ion, which is the anion in potassium iodide
Note that the potassium ions and nitrate ions are spectators in the reaction, meaning they are present before and after the reaction and do not participate in the formation of the insoluble salt.
Pb(NO3)2 (aq) + 2KI (aq) → PbI2 (s) + 2KNO3 (aq)
Where:
Pb(NO3)2 (aq) is lead (2) nitrate in aqueous solution
2KI (aq) is potassium iodide in aqueous solution
PbI2 (s) is lead (2) iodide, the insoluble salt
2KNO3 (aq) is potassium nitrate in aqueous solution
The ionic equation for this reaction is:
Pb2+ (aq) + 2NO3- (aq) + 2K+ (aq) + 2I- (aq) → PbI2 (s) + 2K+ (aq) + 2NO3- (aq)
Where:
Pb2+ is lead (2) ion, which is the cation in lead (2) nitrate
NO3- is nitrate ion, which is the anion in lead (2) nitrate and potassium nitrate
K+ is potassium ion, which is the cation in potassium iodide and potassium nitrate
I- is iodide ion, which is the anion in potassium iodide
Note that the potassium ions and nitrate ions are spectators in the reaction, meaning they are present before and after the reaction and do not participate in the formation of the insoluble salt.
1 answer