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What mass of silver can be produced by reacting 0.300 L of 0.100 M AgNO3 with an excess of Mg?

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.1 M AgNO3 equals .1M Ag

convert to moles, then to grams

Mg + 2AgNO3 ==> 2Ag + Mg(NO3)2
mols AgNO3 = M x L
mols Ag = mols AgNO3
g Ag = mols Ag x atomic mass Ag.

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