Ask a New Question

what mass of lead (ii) iodide (pbl2, mass=461 amu)is precipitated by the addition of an excess of potassium iodide (ki, mass=166 amu)to 50.0 ml of 0.60 m lead (ii) nitrate (pb(no3)2, mass=331.2 amu)?

Ask a New Question or answer this question.

Similar Questions

what mass of lead (II) iodide (PbI2, mass= 461 amu)is predictated by the addition of an excess of potassium iodide (KI, mass=166
1. 1 answer
A solution containing excess lead(ii) nitrate is reacted with 380.0ML of 0.250mol/L potassium iodide solution. A bright yellow
1. 1 answer
A solution with a volume of 1·00 dm3 is saturated with lead iodide, Pbl2. The concentration of iodide ions is 2·7 mol
1. 1 answer
A 0.5917 g sample of a pure soluble chloride compound is dissolved in water, and all of the chloride ion is precipitated as AgCl
1. 1 answer

more similar questions