A 0.5917 g sample of a pure soluble chloride compound is dissolved in water, and all of the chloride ion is precipitated as AgCl by the addition of an excess of silver nitrate. The mass of the resulting AgCl is found to be 1.5683 g.

What is the mass percentage of chlorine in the original compound?

1 answer

mols AgCl = grams/molar mass
Is it % Cl2 you want and not chloride?
(I suspect it is chloride) but I'll stick to what you posted.
g Cl2 = (1.5683g AgCl x (molar mass Cl2/2*molar mass AgCl)
Then %Cl2 = (g Cl2/mass sample)*100 = ?