What mass of lead (II)chloride would precipitate if a solution containing 8,28 g of lead (II) ions(Pb2+) reacts with excess HCl?

Answer 1

Pb^2+ + HCl ==> PbCl2 + 2H^+
mols Pb^2+ = grams/atomic mass
Convert mols Pb^2+ to mols PbCl2 (Use the coefficients to do this)
Convert mols PbCl2 to grams. g = mols x molar mass.