7 grams of chloride was dissolved in water. 20 ml of lead(II)nitrate was used to completely precipitate all chloride (assume atomic mass of 35g/mol). What is the molarity of the Lead(II) Nitrate solution.

Answer 1

2Cl^- + Pb^2+ ==> PbCl2

mols Cl^- = grams/atomic mass Cl.
mols PbCl2 = 1/2 that.
mols Pb^2+ = mol PbCl2.
mols Pb(NO3)2 = mols PbCl2.
M Pb(NO3)2 = mols Pb(NO3)2/L soln.

Answer 2

DrBob222, Is the answer 5M?

Answer 3

Yes

Answer 4

thank you