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What mass of ethanoic acid would you use and how would you prepare 0,500 dm3 of a 0,500 mol/ dm3 ethanoic acid solution? (molecular mass of ethanoic acid=60,0 g/mole)?
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(0,500 dm3)(0,500 mol/ dm3) = 0,250 mol ethanoic acid.
(0,250 mol)(60,0g/mol) = 15,0 grams of ethanoic acid.
Preparation:
*Weigh 15,0g of pure ethanoic acid OR calculate the volume by dividing 15,0g by its density.
*Transfer quantitavily the ethanoic acid into a 500,0 mL volumetric flask.
*Add distilled water up to the mark.
*Place the stopper firmly put you hand over it and mix by inverting 20 times.
*Transfer into a clean and labeled flask.
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Please note: I tried hard to use commas in the place of decimal points which is the custom here (USA). I gave you a more detailed answer than we usually do. Thank you for using our boards.
What mass of ethanoic acid would you used and how would you prepare 0,500 dm3 of a 0,500 mol dm3 ethanoic acid solution? (M of ethanoic acid=60,0)
1 answer