What mass of baking soda (NaHCO3) would be required to neutralize 10.00mL of 12.1M muriatic acid remaining in a empty water bottle?

Answer 1

muriatic acid is HCl.

HCl + NaHCO3 ==> NaCl + H2O + CO2

mols HCl = M x L = ?
mols NaHCO3 = mols HCl since 1 mol HCl reacts with 1 mol NaHCO3.
Then g NaHCO3 = mols NaHCO3 x molar mass NaHCO3.

Answer 2

By M x L do you mean Molarity (12.1) x Liters or moles x Liters?

Answer 3

Nevermind. I am an idiot.