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What mass of ammonia (NH3), is necessary to react with 2.1 x 1024 molecules of O2? 4 NH3 + 7 O2 = 6 H2O + 4 NO2?

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well, 2.1*10^24 molecules = (2.1*10^24)/(6.02*10^23) = 3.488 moles of O2

4/7 that many moles of NH3 are needed
multiply that by the molar mass of NH3.

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