pH = 11.5
pOH = 14 - 11.5 = 2.5
pOH = -log(OH^-) ] 2.5
(OH^-) = ??
KOH ==> K^+ + OH^-
This is a strong base.
You have the (OH^-) which is mols/L. Take 1/2 that to find the mols in 500 mL, Then grams = mols x molar mass. Post your work if you get stuck.
What mass in grams of potassium hydroxide is cntained in 500 mL of solution that has a pH of 11.5?
1 answer
1 answer