Since 1 dm^3 = 1L,
.125 mol/dm^3 = .125M solution
So, the 250mL amount needs
.125*.250 = 0.03125 moles of KOH
multiply that by the molar mass of KOH to get the number of grams.
Brandon prepares a potassium hydroxide solution (KOH) that he uses during a titration to determine the unknown concentration of a hydrochloric acid solution
calculate the mass of potassium hydroxide that is need to prepare 250 cm^3 of a standard 0,125 mol.dm^-3 KOH solution.
1 answer
1 answer