Using the rules...
S= +6 do you agree?
what is theoxidation state of sulfur in Fe2(SO4)3?
2 answers
indeed it is +6. From this compound, there are several things you can get out from it:
The Iron must be Fe(III) and not Fe(II).
The net charge = 0 so 2Fe(III) = +6 so 3(SO4)must = -6 so (SO4) must = -2
Oxygen = -2 because it only contains 6 valence electron (missing 2 to be full).
4 Oxygen = -8 so Sulfur - 8 = -2
Add 8 on both sides as a math equation and you get Sulfur = 6.
The Iron must be Fe(III) and not Fe(II).
The net charge = 0 so 2Fe(III) = +6 so 3(SO4)must = -6 so (SO4) must = -2
Oxygen = -2 because it only contains 6 valence electron (missing 2 to be full).
4 Oxygen = -8 so Sulfur - 8 = -2
Add 8 on both sides as a math equation and you get Sulfur = 6.
1 answer