What is the volume of dry O2 gas at STP, if it had a volume of 5.00 L at 103 kPa and 300 K?

Answer 1

At STP, T = 0 C or 273 K and P = 1 atm or 101.325 kPa.

Assuming the gas ideal, we can use the formula:
P1 * V1 / T1 = P2 * V2 / T2
where
P = pressure
V = volume
T = absolute temperature (in K)
subscripts 1 and 2 = initial and final properties respectively

substituting,
103 * 5 / 300 = 101.325 * (V2) / 273

Now solve for V2. Hope this helps~ `u`

Answer 2

V2= P1V1T2/P2T1
= 103*5*273/101.325*300
=4.63L