x = 2/t
y = ln t
Vx = dx/dt = -2/t^2
Vy = dy/dt = 1/t
so C is correct
What is the velocity vector for a moving particle with a position vector r(t)=(2/t, ln(t))?
a) (2,e^t)
b) (2ln(t), tln(t)) '/>
c) (-2/t^2, 1/t)
d) (ln(t), 2/t)
My answer is "c" but is negative. Can you tell me if my answer is correct?
1 answer
2 answers