What is the value of z in the equation 2(4z − 3 − 1) = 166 − 46?

Group of answer choices

15

17

14

16

1 answer

To solve the equation \( 2(4z - 3 - 1) = 166 - 46 \), we first simplify both sides.

Starting with the right side: \[ 166 - 46 = 120 \] So the equation becomes: \[ 2(4z - 3 - 1) = 120 \]

Now simplify the left side: \[ 4z - 3 - 1 = 4z - 4 \] Thus, the equation is now: \[ 2(4z - 4) = 120 \]

Next, distribute the 2: \[ 8z - 8 = 120 \]

Now, add 8 to both sides: \[ 8z = 128 \]

Next, divide both sides by 8: \[ z = 16 \]

Thus, the value of \( z \) is \( \boxed{16} \).