What is the value of iota to the power iota i.e.i^i
2 answers
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assuming you mean i = √-1, then since
i = 1 cis π/2,
i^i = 1 cis (π/2 i)
= cos(π/2 i) + i sin(π/2 i)
= cosh(π/2) - sinh(π/2)
= e^(-π/2)
i = 1 cis π/2,
i^i = 1 cis (π/2 i)
= cos(π/2 i) + i sin(π/2 i)
= cosh(π/2) - sinh(π/2)
= e^(-π/2)