To find the value of \( \frac{4^6}{4^8} \), you can use the property of exponents that states \( \frac{a^m}{a^n} = a^{m-n} \).
Applying this to the expression:
\[ \frac{4^6}{4^8} = 4^{6-8} = 4^{-2} \]
Now, \( 4^{-2} \) can be rewritten as \( \frac{1}{4^2} \).
Calculating \( 4^2 \):
\[ 4^2 = 16 \]
Thus,
\[ 4^{-2} = \frac{1}{16} \]
So the value of \( \frac{4^6}{4^8} \) is \( \frac{1}{16} \).
The correct answer is:
1 over 16.