What is the upper bound of the infinite sequence 1/x^2, where xE{R\0}
We know that x={1, 1/4, 1/9, 1/16,.....}
Since all x here are greater than 0 or less than equal to 1.
Can't we take 1 as an upper bound here(My tutorial instructor has mentioned so in an answer sheet) I'm confused. Can someone explain? Thanks!
2 answers
Clearly 1 is the least upper bound, since all of the other terms are less than 1, and in fact the largest term is exactly 1.
Thank you very much!
1 answer