what is the theoretical yield of aluminium oxide in grams

Answer 1

To determine the theoretical yield of aluminum oxide, we need to know the balanced chemical equation for the reaction in which aluminum oxide is produced.

The balanced equation for the reaction of aluminum with oxygen to produce aluminum oxide is:
4 Al + 3 O2 -> 2 Al2O3

According to the equation, for every 4 moles of Al reacted, we will obtain 2 moles of Al2O3.

Now, we need to know the molar mass of Al2O3. The molar mass of Al is about 27 g/mol, and the molar mass of O is about 16 g/mol. Therefore, the molar mass of Al2O3 is:
2(27 g/mol) + 3(16 g/mol) = 102 g/mol

Assuming we have 1 mole of Al, by stoichiometry, we'll obtain 2 moles of Al2O3, which corresponds to a mass of:
2 moles Al2O3 x 102 g/mol = 204 g Al2O3

Therefore, the theoretical yield of aluminum oxide is 204 grams.