Lead(II) carbonate decomposes to form Lead(II) oxide and carbon dioxide. If 5.oo grams of the reactant decomposes to produce 1.52 grams of Lead(II) oxide experimentally, what is the theoretical yield and percent yield.

Answer 1

PbCO3 ---> PbO + CO2

First, calculate theoretical yield:

5.00g*(1 mole/267.21 g) = moles of PbCO3

moles of PbCO3=moles of PbO

moles of PbO*(223.20 g/mole)= mass of PbO

mass of PbO=theoretical yield

(1.52g/theoretical yield)*100= % Yield

Answer 2

when heated lead nitrate decomposes to lead oxide, nitrogen dioxide and oxygen gas