The surface area of a square pyramid is the sum of the area of its base and the area of its four triangular faces.
The area of the base can be found by squaring the length of one of its sides, since it is a square. Therefore, the area of the base is 8 ft. * 8 ft. = 64 ft.².
The area of each triangular face can be found using the formula A = (1/2) * base * height, where the base is the length of one side of the square base of the pyramid and the height is the given slant height.
Each triangular face has a base of 8 ft. and a height of 16 ft. Using the formula, the area of each triangular face is (1/2) * 8 ft. * 16 ft. = 64 ft.².
Since there are four triangular faces, the total area of the triangular faces is 4 * 64 ft.² = 256 ft.².
Therefore, the total surface area of the square pyramid is the sum of the base area and the triangular face area, which is 64 ft.² + 256 ft.² = 320 ft.².
So, the correct answer is 320 ft.².
What is the surface area of a square pyramid where the base edge is 8 ft. and the slant height is 16 ft.?(1 point) Responses 320 ft.2 320 ft. squared 256 ft.2256 ft. squared 128 ft.2 128 ft. squared 512 ft.2512 ft. squared
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