The Surface Area of a Square Pyramid is 112 sq. ft. If the Length of Each Edge of the Base is 8 ft, what is the Height of each Triangular Face?

Answer 1

Total surface area = 112 sq.ft
area of base = 8²=64 sq. ft
Area of 4 slant faces = 112-64 = 48 sq.ft
Area of each slant face = 48/4=12 sq. ft
base of slant face = 8
Let H=height of slant face
8*H/2=12 sq.ft
H=3 ft.