To find the x-intercepts, we need to set f(x) = 0 and solve for x.
0 = 3x^2 -11x -4
We can use the quadratic formula to solve for x:
x = (11 ± √(11^2 - 4(3)(-4)))/(2(3)) = (11 ± √169)/6 = (11 ± 13)/6
So the x-intercepts are x = 4/3 (when we use the + in the ±) and x = -1 (when we use the - in the ±).
The sum of these x-intercepts is 4/3 + (-1) = 1/3.
Therefore, the answer is 1 1/3.
What is the sum of the x-intercepts of the function below?
f(x) = 3x^2 -11x -4
1 1/3
-1 1/3
3 2/3
-3 2/3
3 answers
WRONG answer by the bot.
0 = 3x^2 -11x -4
it factors:
(x - 4)(3x + 1) = 0
x = 4 or x = -1/3
sum of the x-intercepts
= 4 - 1/3
= 11/3
0 = 3x^2 -11x -4
it factors:
(x - 4)(3x + 1) = 0
x = 4 or x = -1/3
sum of the x-intercepts
= 4 - 1/3
= 11/3
or, since the roots are
(-b+√(b^2-4ac))/2a and (-b-√(b^2-4ac))/2a the sum is
-b/a = 11/3
which we already knew
(-b+√(b^2-4ac))/2a and (-b-√(b^2-4ac))/2a the sum is
-b/a = 11/3
which we already knew