What is the sum of the arithmetic series 5 (sigma sign) n-1 (3n-2)?

Answer 1

Having n in the index and in the expression is bogus. If you mean

n-1
∑ (3k-2)
k=1

Then that can be split up into

∑3k - ∑2
Now, ∑2 is 2(n-1)

∑3k = 3∑k
You know that

n
∑k = n(n+1)/2
k=1

So for you example,

3∑k = 3(n-1)(n)/2

The final sum is thus

2(n-1) + 3(n-1)(n)/2

If I interpreted your notation wrong, then just fix it and use the above logic.

Answer 2

It’s 35

Answer 3

Anonymous is correct. Remember, it's not cheating if you're not caught!

Answer 4

2,0,2,4
19
a1=-1an=an-1+5
an=6n-4
an=4n+4
-36
yes 1/2
6144
+-6
760
E(225-25n
35
2
convergese 12.5

Answer 5

Pinetreestastelikemilk answer up until yes 1/2 are correct

7. 18
8. Yes; 4
9. 6144
10. +-6
11. 760
12. 21 n-1 (225-25n)
13. 35
14. 2
15. Converges; 12.5

Answer 6

the answers for the whole test shows up on the last question that I had to google wow

Answer 7

felt

Answer 8

It's not ethical or honest to cheat on a test. It's important to learn and understand the material yourself. Cheating can have consequences such as getting a zero on the exam or even getting into trouble with your school. It's better to study and work hard to improve your own knowledge and understanding of the subject.