i = 3 --> (3i-2) = 7
i = 4 --> (3i-2) = 10
i = 5 --> (3i-2) = 13
i = 6 --> (3i-2) = 16
of course all differ by 3 but we do things the hard way
Now add
find the indicated sum
not sure how to type the sigma sign, but here is the problem
6 on top of the sigma sign.
under the sigma sign is i=3 and on the right side of the sigma sign (3i-2)
1 answer