heat lost by object + heat gained by water = 0
[mass object x specific heat object x (Tfinal-Tinitial)] + [mass H2O x specific heat H2O x (Tfinal-Tinitial)] = 0
Substitute the numbers from the problem and solve for specific heat object.
What is the specific heat of an object that weighs 25 g and when heated to a temp of 500K and dropped into 100mL of water changes the temp of the water from room temp (293K) to 306K? Cp of water= 4.184
1 answer
1 answer